Question

A cube of side 'a' units is vertically cut in to two halves. What is the total
surface area of each half ?​

Answer 1

Answer:

8(a^2)

Step-by-step explanation:

Initial surface area of the cube will be 6a^2

After cutting each half of the cube will have 2 sides with surface area= a^2 =>2(a^2)

and 4 sides with surface area=(a/2)a => (4)((a^2)/2) =2(a^2)

Thus total surface area of both the halves will be

2[2(a^2)+2(a^2)]

= 2[4(a^2)]

= 8(a^2)

Answer 2

Given: A cube of side 'a' units

To find:  Total  surface area of each half.

Solution:

• Very first, the total surface area of the original cube will be 6a² as the side is given as a.

• After cutting a cube in two parts it will become a cuboid, where four surfaces will be rectangle and rest two surfaces will be square.

• So the area of the squares is 2(a)²

                and the area of the rectangles is 4(l x b)

                = 4(a x a/2)

• So adding both, we get

                2a² + 2a²

                = 4a²

Answer:

            So the total surface area of each halve is 4a².