Question

A cube of side length 1mm is placed at
distance a 30 cm from the pole of a concave
minnor of focal length 20 . Its one side
parallel to optical anis a . Find the magnifications
in the volume of the abe​

Answer 1

Answer:

from mirror formula

v

1

+

u

1

=

f

1

v

1

−

45

1

=−

30

1

v=−90 cm

Transverse magnification is

du

dv

=−(

u

v

)

2

dv=−

45

2

90

2

=−4mm

londitudinal magnification is

h

o

h

i

=−

u

v

h

i

=−

45

90

=−2 mm

so volume=4×2×1=8mm

3

Explanation:

pls follow me

Answer 2

Explanation:

• So from the question distance u = - 30 cm focal length of concave mirror f = - 20 cm
• Now we have 1/f = 1/u + 1/v
•                   So – 1/20 = - 1/30 + 1/v
•                   So – 1/20 + 1/30 = 1/v
•                   So – 3 + 2 / 60 = 1/v
•                   Or 1/v = - 1/60
•                      Or v = - 60 cm
• So transverse or lateral magnification = - (v/u)^2
•                                                             = - (60/30)^2
•                                                              = - 2 mm
• Longitudinal magnification = - v/u
•                                            = - 60/30
•                                             = - 2 mm
• So volume
•                  = - 2 x – 2 x 1
•                   = 4 mm^3

Reference link will be

https://brainly.in/question/35436122