A cube of wood of volume of 0.2m3 and density 600kg/m3 is placed in a liquid of density 800kg/m3 . What fraction of the volume of the wood be immersed in the liquid
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Answered by
13
Answer:
Given:
Volume of wood = 0.2 m3
Density of wood = 600 kg/m3
Density of liquid = 800 kg/m3
Solution:
Let the fraction of volume of wood inside liquid be ‘v’.
Weight of liquid displaced = weight of the wood
=> (800)(v)(g) = (600)(0.2)(g)
=> v = 120/800 = 0.15 m3
Thus, fraction of the volume of wood inside liquid is = 0.15/2 = 0.075
Answered by
3
Answer:
0.075
Step-by-step explanation:
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