Question

A cube plus b cube plus c cube minus 3 ABC find a + b + c is equals to 10 and a b + BC + CA is equals to 32

Answer 1

substitute these values in the formula

Answer 2

a"3 + b"3 + c"3 - 3abc = (a+b+c)(ab+bc+ca)

a+b+c=10

ab+bc+ca=32

=10(32)

=320

So a"3+b"3+c"3-3abc=320

Hope this helps you please mark me as brainliest for answering the first