A cubic block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block
just to submerge it under water? [Take, density of water = 10°kg/mºl
(A) 30.1 kg
Answers
Answered by
4
Answer:Volume under water = (30/100)*0.5*0.5*0.5 = 3/80 cubic meter
Volume out of water = (70/100)*0.5*0.5*0.5 = 7/80 cubic meter
Additional weight which can be put to just submerge it = weight of liquid displaced = volume of liquid displaced*density of liquid*gravity
= (7/80)*1000*10= 7000/8 N
Corresponding mass = 7000/8*10 = 700/8 = 87.5kg
Explanation:
Similar questions