A cubical block of dimension
50cm x 30cm x 10cm is kept on the
floor. The weight of the block is
50N
:) Find the least Possible pressure
that would be exerted by the
block when it is kept on the
floor
ii) find the pressure exerted by the
floor when the
area Of contact is smallest
Answers
Answered by
1
Answer:
Explanation:
Area = 3cm×3cm=9cm
2
=9×10
−4
m
2
& Pressure exterted = 5Pa
Since Pressure =
Area
Force
Force = Pressure × Area
Force = 9×10
−4
×5N
= 45×10
−4
N.
Answered by
0
Answer:
here is the answer.
hope it helps.
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