Question

A cubical block of mass 1000kg is kept on a levelled horizontal surface.If it exerts a pressure of 100pa on the surface,then find the volume of the block.​

Answer 1

Answer:

mass of cubical mass is 1000kg .

pressure is 100 pa .

g= 10m/S2

pressure = force / area .

force= mass × g

1000=1000×10/A

A= 10meter square.

side of cuboidal block = 10 m

volume of block =(10)3= 1000meter 3.

Answer 2

Given:

Mass of block = 1000 kg

Pressure exerted = 100 Pa

To find:

Volume of the block

Solution:

Step 1

We have been given that the block of mass 1000 kg exerts a pressure 100 Pa on the horizontal.

Therefore,

The force exerted by the block on the ground is nothing but the weight of block given by

F = mg = 1000 × 10

F = 10⁴ N

Step 2

Now,

We know, pressure is given by

$P=\frac{F}{A}$

Where, A is the area of the surface in contact with the horizontal.

Hence, Area = $(side)^{2}$

Substituting the known values in the equation, we get

$100 =\frac{10^{4} }{A}$

Therefore,

A = 100 m²

(side)² = 100   ; or

side = 10 m

Step 3

Now,

We know, volume of cube = (side)³

Substituting the given value, we get

V = (10)³

V = 1000 m³

Final answer:

Hence, the volume of the cubical box will be 1000 cubic meter.