हाउ मेनी इलेक्ट्रोंस आर प्रेजेंट इन 4.4 ग्राम ऑफ कार्बन डाइऑक्साइड
Answers
Answered by
1
Moles of CO
2
=
44
4.4
=0.1 moles
∴ Number of molecules of CO
2
=0.1×6.022×10
23
=6.022×10
22
molecules
But 1 molecule of CO
2
contains 2 oxygen atoms.
∴ Number of oxygen atoms=2×6.022×10
22
=12.044×10
22
atoms
=1.2×10
23
atoms
2
=
44
4.4
=0.1 moles
∴ Number of molecules of CO
2
=0.1×6.022×10
23
=6.022×10
22
molecules
But 1 molecule of CO
2
contains 2 oxygen atoms.
∴ Number of oxygen atoms=2×6.022×10
22
=12.044×10
22
atoms
=1.2×10
23
atoms
Answered by
0
Answer:
calculate it.
Explanation:
6.023 X 10²³ molecules are present in 1 gram
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