Question

A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water?
[Take density of water = 10³ kg/m³]
(A) 46.3 kg (B) 65.4 kg
(C) 30.1 kg (D) 87.5 kg

Answer 1

$\huge\bold{30.1kg}$

Answer 2

Given :

Length of side = 0.5m

Volume under water = 30V/100

To find :

The maximum weight that ca be put on the block = ?

Solution :

• Buoyancy force = Mg

       (ρ×30V×g/100) = Mg

       M = 1000×3 / 100×8

       M = 300/8 kg

• B = (M+m)g

      ρVg = (M+m)g

      1000/8 = 300/8  +m

        m = 700 / 8

        m = 87.5 kg

The maximum weight that ca be put on the block is 87.5 kg