a cubical block of side 14 cm is surmounted by a hemisphere of maximum diameter. find the surface area of the solid
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Answer:
A cubical block of side 14 cm is surmounted by a hemisphere.
To find:
What is the greatest diameter the hemisphere can have?
Find the surface area of the solid.
Solution:
From given, we have,
The side of a cubical block = a = 14 cm
⇒ The diameter of the hemisphere surmounted = d = 14 cm
Therefore, the greatest diameter the hemisphere can have is equal to the side of a cubical block.
⇒ The radius = r = d/2 = 14/2 = 7 cm
∴ r = 7 cm
Surface area of the solid = Area of cube + Curved surface area of hemisphere - Base area of hemisphere
⇒ Surface area of the solid = 6a² + 2πr² - πr²
⇒ Surface area of the solid = 6a² + πr²
= 6(14)² + 22/7 × 7²
= 1176 + 22 × 7
= 1176 + 154
= 1330
∴ The surface area of the solid is 1330 sq cm.
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