Question

A cubical block of side 2 cm is lying on a table. If the mass of the material of the cube is 2 kg, find the pressure exerted by the block on the table. [Take g= 9.8 m/s²]

Topic: Floatation.

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Answer 1

Please refer the attachment for tge solution of your question

I have tried it on my own

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Answer 2

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$\huge\bold\purple{Solution:-}$

♨ Answer:-

P= 4.9 × 10⁴ Pa.

♨ Step-by-step explanation:-

As given,

m= 2 kg,

W= mg = 2 × 9.8 = 19.6 N.

Side= 2 cm = 2/100 m = 0.02 m.

Now,

Area of lower face of the cube = (side)²

= (0.02)² = 4 × 10^-4 m²

We know that,

P = F/A

=> P = 19.6/4 × 10^-4

=> P= 4.9 × 10⁴ Pa. [ The required solution..]

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