Question

A cubical block of side 2 cm is lying on a table .if the mass of the material of the cube is 2 kg.Find the pressure exerted by the block on the table.

Answer 1

The pressure exerted by the block on the table is 50 K.Pa

Explanation:

Given data:

Mass , m = 2 kg

Side of the cube, a = 2 cm = 0. 02 m

Area = a² = 0. 02 × 0. 02 = 0.0004 m

Solution:

Pressure =  Force / Area

= mg / area  

= 2 × 10 ÷ 0.0004

= 50000 Pa = 50 K.Pa

Thus the pressure exerted by the block on the table is 50 K.Pa

Also learn more

A brick is 32 cm long,10 cm wide and 10 cm thick.it weighs 16 N & is lying on the  ground. Find the pressure exerted by the brick on the ground.

https://brainly.in/question/1181696

Answer 2

$\huge\underline\mathbb{ANSWER}$

$m = 2kg \\ W = mg = 2 \times 9.8 = 19.6N \\ \\ Area \: of \: lower \: face \: of \: cube = ( {side})^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( {0.02})^{2} \: = 4 \times {10}^{ - 4} {m}^{2} \\ \\ P = \frac{F}{A} \: = \frac{19.6}{4 \times {10}^{ - 4} } \\ P = 4.9 \times {10}^{ - 4} \: Pa$

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