Question

A cubical block of water is dipped completely in
water. Each edge of the block is 1cm in length. Find the buoyant force acting
on the block

Answer 1

length of edge of cubical ice block = 1 cm
volume of the block (V)= 1³ cm³ = 10^(-6) m³
density of water (Dw)= 10³ kg/m³

buoyant force = Dw×V×g = 10³ × 10^(-6) × 10 = 10^(-2) N = 0.01 N

Answer 2

Buoyant force acting vertically upwards on the object = weight of the water displaced
    = density of water * volume of block * g = 1 gm / cm³ * 1cm³ * 981 cm/sec² 
    = 981 dynes
    = 0.00981 Newtons