Question

A cubical block of wood of density 5 gram/cm^-3 stands on a table with a side of 10cm. Find the thrust by the block of wood on the table if g=10ms^-2​

Answer 1

Answer:

Side a = 10cm = 0.1m

So Volume = a

3

=0.001m

3

orV=1000cm

3

.

So mass = 5g/cc×1000cc=5000gm=5kg

hence upthrust = 5kg×g=50N.

Explanation:

Hope it helps