A cubical block of wood of side 5 cm is placed on a table. Find the thrust by the wooden block on the table, if density of wood is 5 gcm−3 and g is 10ms−2.
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Answer:
250N
Explanation:
as the side of the cube is 5cm then it's area becomes
5*5=25
and the value of G is given 10
force/Thrust= force * area
Thrust=10*25=250 Newton
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