A cubical box of side 1m is immersed a uniform
electric field of strength 10000 N/C. The flux
through the cube is-
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Given ,
Side of the cube = 1 m
Electric field = 10000 N/C
We know that ,
The total number of electric field lines passing through the given area is called electric flux
Thus ,
Φ = (10)^4 × 6 × (1)²
Because , TSA of cube is 6 × (side)²
Φ = 6 × (10)^4
Hence , 6 × (10)^4 electric flux passing through the cube
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