a cubical box of wood of side 30 cm weighing 21.6 kg floats on water with two faces horizontal. the depth of immersion of box is
a) 12cm b) 5cm. c)24 cm
d) 10 cm
Answers
Answered by
15
30 × 30 × 10^-4 × h × g = 21.6
Let h = the depth of immersion then
H= 24
Answer- c)24
Answered by
46
Hey buddy,
◆ Answer-
(c) h = 24 cm
◆ Explaination-
# Given-
s = 30 cm = 0.3 m
m = 21.6 kg
# Solution-
Let h be depth of immersion and Vi bs volume of immersed part.
Here, liquid displaced is equal to weight of wooden block.
mg = Vi.ρ0.g
m = s×s×h.ρ0
21.6 = 0.3^2 × 1000 × h
h = 0.24 m
h = 24 cm
Therefore, depth of immersed part is 24 cm.
Hope it helps...
◆ Answer-
(c) h = 24 cm
◆ Explaination-
# Given-
s = 30 cm = 0.3 m
m = 21.6 kg
# Solution-
Let h be depth of immersion and Vi bs volume of immersed part.
Here, liquid displaced is equal to weight of wooden block.
mg = Vi.ρ0.g
m = s×s×h.ρ0
21.6 = 0.3^2 × 1000 × h
h = 0.24 m
h = 24 cm
Therefore, depth of immersed part is 24 cm.
Hope it helps...
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