Math, asked by sarojroy385gmailcom, 1 month ago


A cubical box with edge 20 cm is filled with smaller cubes of sides 5 cm each
How many of these small cubes can fit into the the larger box .​

Answers

Answered by abhinavjoshi88
2

Answer:

64 boxes

Step-by-step explanation:

n( volume of smaller boxes ) = Volume of the larger box

[where 'n' is the number of boxes]

=> n( 5×5×5 ) = 20×20×20

=> 125n = 8000

=> n = 8000/125 = 64

Answered by aryunguptaespn
2

Answer:

Step-by-step explanation:

Answers no. 1

In a square of 20 cm x 20 cm you can place 4 x 4 squares of 5 cm x 5cm. So there are 16 smaller squares in one layer and you can have 4 layers in the height of 20 cm. So you can fit 64 cubes of 5 cm side in the cubical box of side 20 cm.

Volume of the 5 cm cube is 5 x 5 x 5 cc. The volume of the cubical box is 20 x 20 x 20 cc. So the number of 5 cm cubes that can be fitted in the cubical box, N = [20 x 20 x 20 cc] /[5 x 5 x 5 cc] = 4 x 4 x 4 = 64 cubes.

Answers no. 2

Number of small cubes = ( volume of larger cubical box) ÷ ( volume of a small cube)

⇒ Volume of cube = side^3 cubic unit

⇒ No of cubes = ( 20 * 20 * 20) ÷ ( 5 * 5 * 5)

⇒ 64 cubes

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