A cubical box with lid has a length of 30cm.find the cost of painting the inside and outside of the box at rupees 5.50 pretty square meter
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❤❤❤hay.....❤❤❤
plzz... mark it as brainlist
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it is your answer ....
⚓⚓⚓⚓⚓⚓⚓⚓
total surface area of cube
=6× side^2
given......
side = 30cm =0.3 m
if box are closed ..
then......
S.A of inside = S.A OF outside
total surface area of box
to be pented....
S.A of inside + S.A OF outside
= 2×6× side^2
= 12× (0.3)^2
= 1.08 m^2
now cost of painting..
= 5.50×1.08
=5.94 rupees...
answer......
➖➖➖➖➖➖➖➖➖➖➖➖
plzz... mark it as brainlist
✔✔✔✔✔✔✔✔✔
it is your answer ....
⚓⚓⚓⚓⚓⚓⚓⚓
total surface area of cube
=6× side^2
given......
side = 30cm =0.3 m
if box are closed ..
then......
S.A of inside = S.A OF outside
total surface area of box
to be pented....
S.A of inside + S.A OF outside
= 2×6× side^2
= 12× (0.3)^2
= 1.08 m^2
now cost of painting..
= 5.50×1.08
=5.94 rupees...
answer......
➖➖➖➖➖➖➖➖➖➖➖➖
Answered by
1
❤❤❤hay.....❤❤❤
✔✔✔✔✔✔✔✔✔
total surface area of cube
=6× side^2
given......
side = 30cm =0.3 m
if box are closed ..
then......
S.A of inside = S.A OF outside
total surface area of box
to be pented....
S.A of inside + S.A OF outside
= 2×6× side^2
= 12× (0.3)^2
= 1.08 m^2
now cost of painting..
= 5.50×1.08
=5.94 rupees...
answer.....
✔✔✔✔✔✔✔✔✔
total surface area of cube
=6× side^2
given......
side = 30cm =0.3 m
if box are closed ..
then......
S.A of inside = S.A OF outside
total surface area of box
to be pented....
S.A of inside + S.A OF outside
= 2×6× side^2
= 12× (0.3)^2
= 1.08 m^2
now cost of painting..
= 5.50×1.08
=5.94 rupees...
answer.....
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