Three Schools situated at P, Q and R in the figure are equidistant from each other as shown in the figure. Find QOR.
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32
If all sides are equal therefore it's a equilateral triangle in which all angles are equal 60°
p=q=r=60°
in triangle qor
oqr+orq+qor=180
30+30+qor=180
60+qor=180
qor=180-60
qor=120
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p=q=r=60°
in triangle qor
oqr+orq+qor=180
30+30+qor=180
60+qor=180
qor=180-60
qor=120
if you like it mark as brainliest
Answered by
12
Given PQ=PR
THEREFORE IT IS A EQUIDISTANT TRIANGLE =60 °
P=Q=R=60°
IN TRIANGLE QOR
OQR+ORQ+QOR=180°
30°+30°+QOR=180°
QOR=120°
HOPE THIS HELP YOU
MARK ME AS BRAINLIST ❤️❤️✌️✌️
THEREFORE IT IS A EQUIDISTANT TRIANGLE =60 °
P=Q=R=60°
IN TRIANGLE QOR
OQR+ORQ+QOR=180°
30°+30°+QOR=180°
QOR=120°
HOPE THIS HELP YOU
MARK ME AS BRAINLIST ❤️❤️✌️✌️
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