how to calculate the number of moles of KCLO3 that will be required to give 6 moles of oxygen
Answers
Answered by
38
We know that
2KClO3 -----> 2KCl + 3O2
For 6 moles of oxygen,
4KClO3 -----> 4KCl + 6O2
Hence 4 moles are required
2KClO3 -----> 2KCl + 3O2
For 6 moles of oxygen,
4KClO3 -----> 4KCl + 6O2
Hence 4 moles are required
Answered by
22
The balanced equation for decomposition of KClO3 is as follows:
2KClO3 2KCl + 3O2
According to the equation 2 moles of KClO3 gives 3 moles of oxygen (O2).
To obtain 6 moles of oxygen we multiply chemical equation by 2.
4KClO3 4KCl + 6O2
Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.
2KClO3 2KCl + 3O2
According to the equation 2 moles of KClO3 gives 3 moles of oxygen (O2).
To obtain 6 moles of oxygen we multiply chemical equation by 2.
4KClO3 4KCl + 6O2
Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.
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