Question

A cubical rectangular bar has the dimensions with the ratio 5 : 4 : 3. its volume is 7500. what is the surface area of the bar?

Answer 1

Answer:

$2350 unit^2$

Step-by-step explanation:

Let the ratio be x

Since we are given that A cubical rectangular bar has the dimensions with the ratio 5 : 4 : 3.

So, dimensions becomes 5x, 4x, 3x

Formula of volume of cuboid = $Length \times Breadth\ times Height$

Since we are given that the volume of the cuboid is 7500

So,  $7500 =5x \times 4x \times 3x$

$7500 =60x^3$

$\frac{7500}{60} =x^3$

$125 =x^3$

$\sqrt[3]{125}  =x$

$5 =x$

So, Length(l) = 5x = 5*5 =25

Breadth(b) = 4x=4*5=20

Height(h) = 3*5=15

Formula of surface area of cuboid =$2(lb+bh+hl)$

                                                        =$2(25*20+20*15+15*25)$

                                                        =$2350 unit^2$

Hence the surface area of bar is $2350 unit^2$