a cubical vessel of height 1m is full of water the minmum worke done in taking water out from vessel will be
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We will use integration here.
So,w=mgh
h is varying
so, h=x
intergral xdx
x^2/2=h
So,here Mass=Density×volume
=1000×1
=1000kg
g=10m/s^2
h=1/2m
Then,W=1000×10×1/2 J
5000J
Can I ask that you are a student of which class and school bc z same question I have solved with same values
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