a cubodial tank open at the top is made of an iron sheet 4m wide. if the dimensions of the tank are 12m * 8m * 6m find the cost of an iron sheet required to make the tank at Rs.17.50 per metre.
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Length of the tank = L = 12 m
Breadth of the tank = B = 8m
Height of the tank = H = 6 m
Area of the Lateral surface = 2*(L + B)*H = 2*(12 + 8)*6 m^2 = 240 m^2
Area of the Base = L*B = 12*8 m^2 = 96 m^2
Total Surface Area of the open tank = (240 + 96) = 336 m^2 = Area of the iron sheet required = A
width of the iron sheet = W = 4 m
Length of iron sheet required = A / W = 336 / 4 m = 84 m
Cost of iron sheet per meter = Rs17.50
Cost of 84 m of iron sheet = Rs 17.50 * 84 = Rs 1470
Breadth of the tank = B = 8m
Height of the tank = H = 6 m
Area of the Lateral surface = 2*(L + B)*H = 2*(12 + 8)*6 m^2 = 240 m^2
Area of the Base = L*B = 12*8 m^2 = 96 m^2
Total Surface Area of the open tank = (240 + 96) = 336 m^2 = Area of the iron sheet required = A
width of the iron sheet = W = 4 m
Length of iron sheet required = A / W = 336 / 4 m = 84 m
Cost of iron sheet per meter = Rs17.50
Cost of 84 m of iron sheet = Rs 17.50 * 84 = Rs 1470
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Answer:
Given,
Dimensions of tank = 12m×8m×6m
Where,
length = 12 m
breadth = 8 m
height = 6 m
Area of sheet required for making the tank = Total surface area of tank with one top open
=l×b+2(l×h+b×h)=12×8+2(12×6+8×6)=96+240=336 m^2
Let l be the length of iron sheet and b be the breadth of iron sheet.b =4m
l ×b
=336
=84m
So, cost of iron sheet = 17.50×84=1470 Rs
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