A cuboid has a volume of 24 cm3. What can its maximum surface area be, if its length, breadth, and height are integers?
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2
Answer:
76 cm^2
Step-by-step explanation:
Volume of the cuboid = Length(l)×breadth(b)×Height (h)
Given that
A cuboid has a volume of 24 cm^3 and its length, breadth, and height are integers only.
prime factor of 24 = 2^3\times3\times1
24 = 2×3×2×2×1
24= 12×2×1
or 24= 6×4×1
Now, for Surface area to be maximum we have to take dimensions as
12,2,1
SA = 2(lb+lh+bh)
=2(12×2+12×1+2×1)
= 76 cm^2
Therefore, maximum area of the cuboid with diemensions, 12,2,1 = 76 unit
Answered by
0
Answer:
Answer is 76 cm^2
Step-by-step explanation:
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