Question

A man does a work of 2000 J in dragging a sack of cement through a distance of 40 m. What is the magnitude of force applied by the man?

Answer 1

Answer :

• Magnitude of force required = 50 Newton

Given :

• Work done by Man, W = 2000 J
• Displacement of sack while dragging, s = 40 m

To find :

• Magnitude of force applied, F =?

Formula required :

• Formula to calculate Work done

        W = F  s

[Where W is the work done by a body on applying a force F to cover a displacement of s, where Direction of force and displacement is same]

Solution :

Using Formula to calculate Work done

→ W = F s

→ 2000 = ( F ) ( 40 )

→ F = 2000 / 40

→ F = 50  N

Therefore,

• Magnitude of Force required in moving given sack is 50 Newton.

Answer 2

Answer:

Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

• Work = 2000 J
• Displacement = 40 m
• Force = ?

• According to the Work Definition :

⇒ Work = Force × Displacement

⇒ 2000 J = Force × 40 m

⇒ 2000 J ÷ 40 m = Force

⇒ Force = 50N

∴ Magnitude of Force applied is 50N.