A cuboid having dimensions 4 m × 2 m × 1.5 m is cut from a cuboid measuring 24 m × 12 m × 3 m . Find the volume of the remaining solid .
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l×b×h=4×2×1.5m
L×B×H=24×12×3
volume of big cuboid=L×B×H
=24×2×3
volume of small cuboid=l×b×h
=4×2×1.5
remaining solid =volume of big cuboid - volume of small cuboid
=24×2×3-4×2×12. 5
=132m^3
L×B×H=24×12×3
volume of big cuboid=L×B×H
=24×2×3
volume of small cuboid=l×b×h
=4×2×1.5
remaining solid =volume of big cuboid - volume of small cuboid
=24×2×3-4×2×12. 5
=132m^3
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