Question

A cuboid is 20m×10m×8m.Find its length of the diagonal, surface area,volume.

Answer 1

diagonal = root ((20*20)+(10*10)+(8*8))
              = root (400+100+64)
              = root (564)
              = 23.7 m

Answer 2

Given,
Dimensions of cubiod=20m,10m,8m
therefore,
Length of diagonal =
$\sqrt{} {a}^{2} + {b}^{2} + {c}^{2}$
√20×20+10×10+8×8
=√400+100+64
=√564
=2√141

(Total)surface are=2(lb+lh+bh)
=2(20×10+20×8+10×8)
=2(200+160+80)
=2(340)
=680

volume of cuboid=lbh
=20×10×8
=200×8
=1600


therefore,diagonal=2√141
surface area=680
volume=1600