Math, asked by rajivroman9, 9 months ago

A cuboid is 3cm by 4cm by 7cm. Explain whether doubling all of the dimensions would double the surface area?

Answers

Answered by ItsUDIT
11

Step-by-step explanation:

It is given a cuboid having dimension,

length, l = 7 cm

breadth, b = 4 cm

height, h = 3 cm

Now, We know that,

surface area of cuboid = 2(lb +bh +hl)

So, the surface area ,

S1 = 2( 7×4 + 4×3 + 3×7 )

=> S1 = 2( 28 + 12 + 21)

=> S1 = 2 × 51

Now, after doubling the dimension,

we have , new dimensions,

l' = 7×2 = 14 cm

b' = 4×2 = 8 cm

h' = 3×2 = 6 cm

So,the new surface area,

S2 = 2(14×8 + 8×6 + 14×6 )

=> S2 = 2 × 244

Clearly, we can see that

2S1 ≠ S2

Answered by johnkannamkulam
1

Answer:

intial SA=122 by doubleing SA=488 SA is four times the intial SA

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