a cuboid is formed of 3 edges measuring 3 cm, 4 cm and 5 cm. it is sliced in to two identical solids by a plane through a diagonal of the smallest of the faces. find the surface area of the sliced section?
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When the cube is sliced into two identical solids through a diagonal of the smallest faces, then the sides will be 3 cm and 4 cm, through which it is sliced.
Length of the diagonal of the smallest of faces = √3²+4²
√9+16
√25
Length = 5 cm
Therefore, the area of the sliced section = 5 × 5
= 25 cm²
Answer.
When the cube is sliced into two identical solids through a diagonal of the smallest faces, then the sides will be 3 cm and 4 cm, through which it is sliced.
Length of the diagonal of the smallest of faces = √3²+4²
√9+16
√25
Length = 5 cm
Therefore, the area of the sliced section = 5 × 5
= 25 cm²
Answer.
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