Question

a cuboid of measurement (64) (54) (30) how many cubes with side 6 can be placed in cuboid
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Answer 1

Step-by-step explanation:

Vol. of cuboid = 64 × 54 × 30 = 103680

Now vol. of cubes =

$(6) {}^{3} = 216$

Now, we know that

$n \: \times \: vol \: of \: cube \: = vol \: of \: cuboid$

so,

$n \times 216 = 103680 \\ n = \frac{103680}{216} \\ n = 480$

so, 480 Cubes will be needed ..

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Answer 2

Answer:

vol. of cube =6^3

=216

vol. of cuboid=64*54*30

=3456*30

=103680

thus,103680/216

=51840/108

=25920/54

=12960/27

=4320/9

=480

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Step-by-step explanation: