a cuboid shaped slab of iron whose dimensions are 55cm×40 cm ×15 cm are melted and recarted to a Pipe . The outer radius and thickness are 4 cm and 1 cm respectively. find length of the cylinder
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given,
cubical shaped iron slab
length=55 cm
breadth=40 cm
height=15 cm
now slab melt and form pipe
outer radius of pipe=4cm
inner radius =(4-1)=3cm
length=?
now
volume of iron slab =volume of cylinder pipe
=> 50 x 40 x 15 =pi. {R^2-r^2}.h
=> 50 x 40 x 15 =22/7 x (16-9) x h
=> 50 x 40 x 15 =22/7 x 7 x h
h= 50 x 40 x 15/22 cm=1363.63 cm
cubical shaped iron slab
length=55 cm
breadth=40 cm
height=15 cm
now slab melt and form pipe
outer radius of pipe=4cm
inner radius =(4-1)=3cm
length=?
now
volume of iron slab =volume of cylinder pipe
=> 50 x 40 x 15 =pi. {R^2-r^2}.h
=> 50 x 40 x 15 =22/7 x (16-9) x h
=> 50 x 40 x 15 =22/7 x 7 x h
h= 50 x 40 x 15/22 cm=1363.63 cm
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