Question

A cuboidal shaped geometry box has volume of 289cc. If its length is 17 cm, breadth is 8.5 cm , then what will be the thickness of the box ?​

Answer 1

Answer:

• Thickness of the geometry box is 2.26 cm.

Step-by-step explanation:

Given that:

• Volume of a cuboidal shaped geometry is 289 cm³.
• Length of the geometry box is 17 cm.
• Breadth of the geometry box is 8.5 cm.

To Find:

• Thickness (Height) of the geometry box.

As we know that:

Area of a cuboid = (L × B × H) cm³

Where,

• L = Length
• B = Breadth
• H = Height

Substituting the values,

$\sf{289=15\times8.5\times H}$

Multiplying the numbers on RHS,

$\sf{\longrightarrow 289=127.5\times H}$

Transposing 127.5 from RHS to LHS and changing its sign,

$\sf{\longrightarrow \dfrac{289}{127.5}= H}$

Multiplying both denominator and numerator by 10,

$\sf{\longrightarrow \dfrac{289\times10}{127.5\times10}= H}$

$\sf{\longrightarrow \dfrac{2890}{1275}= H}$

Reducing the numbers,

$\sf{\longrightarrow \dfrac{2890\div85}{1275\div85}= H}$

$\sf{\longrightarrow \dfrac{34}{15}= H}$

Dividing 34 by 15,

$\sf{\longrightarrow 2.26= H}$

Hence, H = 2.26

Therefore, thickness of the geometry box is 2.26 cm.