Question

A cuboidal well of dimension 55 m x 20 m x 7 m is dug and the earth obtained from digging is evenly spread out to form a platform having rectangle base 22 m x 14 m. Find the height of the platform.

Answer 1

Answer:

volume of cuboid=lxbxh

V = 55x20x7=770m3

770 = 22x14xh

h:=770 / 22x14=2.5 meter

height of the platform = 2.5m

Answer 2

Answer:

Height of platform: 25 m

Step-by-step explanation:

Volume of cuboidal well

$\boxed{V = l \times b \times h \: \: {unit}^{3} }$

A cuboidal well of dimension 55 m x 20 m x 7 m is dug

Volume of earth taken out

$= 55 \times 20 \times 7 \\ \\ = 55 \times 140 \\ \\ = 7700 \: {m}^{3}$

Earth obtained from digging is evenly spread out to form a platform having rectangle base 22 m x 14 m,let the platform have height h;

So ,volume of earth taken out = volume of cuboid so formed

$7700 = 22 \times 14 \times h \\ \\ h = \frac{7700}{22 \times 14} \\ \\ h = \frac{700}{2 \times 14} \\ \\ h = 25 \: m$

Height of that rectangular platform will be 25 meter.

Hope it helps you.