Question

If the diameter and the height of a carrom coin are 4 cm and 0.5 cm respectively, find the volume of the cylinder made up of such 12 carrom coins stacked on each other. (π = 3.14)

Answer 1

Answer:

75.36

Step-by-step explanation:

d=4cm

r=d/2=4/2=2cm

h=0.5cm

volume of cylinder made up of 12 carrom coins=12×π×r×r×h

= 12×3.14×2×2×0.5

=37.68×2

=75.36

Answer 2

Answer:

$Volume \: of \: 12\:coins\\= 75.36\: square \: cm$

Step-by-step explanation:

Dimensions of a carrom coin:

$diameter \:(d)= 4\:cm$

$Radius \:(r)= \frac{d}{2}\\=\frac{4}{2}= 2 \:cm$

$Height \:(h) = 0.5 \:cm$

$We\: know \: that ,\\\boxed { Volume \: of \: a \: cylinder (V) = \pi r^{2}h }$

$Volume \: of \: 12 \:coins\\ = 12\times 3.14 \times 2^{2}\times 0.5$

\* π = 3.14 (given )*\

$= 75.36\: square \: cm$

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