A current 2A flows in the electric circuit as shown in the figure. The current through branch AB is
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Answered by
7
Here you can see that wire AB is a conductor of without resistance. it is example of short circuit.
we know, a short circuit is simply a low resistance connection between the two conductors supplying electrical power to any circuit.
basically we assume resistance of short circuit = 0.
now from Ohm's law,
V = IR
V = I × 0
I = V/0 , the value of current through short circuit is vary large { infinite }.
hence, current through branch AB tends to infinity.
we know, a short circuit is simply a low resistance connection between the two conductors supplying electrical power to any circuit.
basically we assume resistance of short circuit = 0.
now from Ohm's law,
V = IR
V = I × 0
I = V/0 , the value of current through short circuit is vary large { infinite }.
hence, current through branch AB tends to infinity.
samarthps29:
friend but the answer is 2/3 A
It's not possible because AB is a wire which has no resistance . Hence, we have to use concept of short circuit.
Answered by
22
Answer:
The current in the branch AB will be 0.66 Amperes.
Explanation:
Explanation :
From the current division rule:
current in the 1st 3Ω resistor in branch PA
= 2 x 6/9
= 4/3 A
current in the 1st 6Ω resistor in branch PB
= 2 x 3/9
= 2/3 A
Again these current will divide to the second parallel set of resistors,
Hence current in 2nd 3Ω resistor in branch BQ from the branch PA
= 4/3 x 6/9
= 8/9 A
similarly current in 2nd 6Ω resistor in branch AQ from the branch PB
= 2/3 x 3/9
= 2/9 A
Hence current in the branch AB
= 8/9 - 2/9
= 6/9
= 0.66A
Hence the current in the branch AB will be 0.66 Amperes
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