Question

a current 4A flows through an automobile headlight. how many electrons flow through the headlight in a time 2hrs​

Answer 1

Answer:

1.8*10^22electron

Explanation:

I=q/t

4A=ne/t

4*1=n*1.6*10^-19

4/1.6*10^-19=n

2.5*10^19=n

number of electron flow in 1second =2.5*10^19

nomber of electron flow in 2hrs =2.5610^19*2*3600(1hrs=3600second)

=18*10^21

=1.8*10^22

Answer 2

Answer:

$n=1.8\times 10^{23}$

Explanation:

Given that

Current flowing through automobile, I = 4 A

Time, t = 2 h = 7200 s

Electric current is given by :

$I=\dfrac{q}{t}$

Since, q = ne

Let n is the number of electrons.

So, $n=\dfrac{It}{e}$

e is the charge of electron

$n=\dfrac{4\times 7200}{1.6\times 10^{-19}}$

$n=1.8\times 10^{23}$

So, the number of number of electrons in the headlight is $n=1.8\times 10^{23}$