A current consists of one ohm in series or parallel arrangement of 6 ohm and 3 ohm calculate the effective resistance
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R1=6ohm
R2=3ohm
in series,
R=R1+R2
=6+3=9ohm
in parallel,
1/R=1/R1+1/R2
=1/6+1/3
1/R=3/6
R=6/3=2
R2=3ohm
in series,
R=R1+R2
=6+3=9ohm
in parallel,
1/R=1/R1+1/R2
=1/6+1/3
1/R=3/6
R=6/3=2
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