a current of 0.2 ampere is draw by the filament of an electric bulb for 30 minute . find the amount of electric charge that flow through the circuit
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I(current)=0.2A
t(time)=30 min=30*60=1800s
I=Q/T
0.2=Q/1800
Q=0.2*1800
Q=360C
hope this helps you.
please mark the answer as the brainliest.
thank you
t(time)=30 min=30*60=1800s
I=Q/T
0.2=Q/1800
Q=0.2*1800
Q=360C
hope this helps you.
please mark the answer as the brainliest.
thank you
mohdaltaf6479:
thnx
Answered by
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I hope this will help you....^-^
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