Question

a current of 1.5 ampere is passed through a solution of a salt of bivalent matter for 30 mint. In u is mass at cathode is 0.8898 find the atomic mass of the matel​

Answer 1

its bivalent

x-> x^2+ + 2e

2F needed to deposit 1 mole

q= 1.5× 30× 60 = 2700

2× 96500 needed to deposit 1 mole

so with 2700c = 2700/2×96500 mole

= 27/1930

27M/1930 = 0.8898

M= 0.8898× 1930/27

= 1717.3/27

= 63.6