Chemistry, asked by fawazrules123, 10 months ago


A current of 1.50 amp was passed through an electrolytic cell containing AgNO3 solution with inert electrodes. The weight of Ag deposited was 1.50g. How long did the current flow? (2marks)

(b) Write the reactions taking place at the anode and cathode in the above cell.​

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Answered by rinkukumar08r3
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12th

Chemistry

Electrochemistry

Electrolytic Cells and Electrolysis

Three electrolytic cells A,...

CHEMISTRY

Three electrolytic cells A,B,C containing solutions of ZnSO

4

,AgNO

3

and CuSO

4

, respectively are connected in series. A steady current of 1.5 amperes was passed through them until 1.45 g of silver deposited at the cathode of cell B. How long did the current flow? What mass of copper and zinc were deposited?

November 22, 2019avatar

Puneetha Adak

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ANSWER

Cell B: Ag

+

+e

⇌Ag at cathode.

1 mole (108 g) of Ag is deposited by 96500 C.

1.45 g of Ag will be deposited by

108

96500×1.45

=1295.6C.

Q=It

1295.6=1.5×t

t=864s

Cell A: Zn

2+

+2e

→Zn

2 moles of electrons (2×96500 C of current) produces 1 mole (63.5 g) of zinc.

1295.6 C of electricity will deposit

2×96500

65.3

×1295.6=0.438 g of zinc

Cell C: Cu

2+

+2e

→Cu

2 moles of electrons (2×96500 C) of current will produce 1 mole (63.5 g) of Cu.

1295.6 C of current will deposit

2×96500

63.5×1295.6

=0.426g of copper

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