Question

A current of 1.6 ma flows through a conductor find thr no. Of electrons passes each sec in the conductor

Answer 1

We have I=1.6ma

I=0.16A (1mA=1/1000)

t=1 sec

By I=q/t

Therefore, q=It

q=0.16×1

q=0.16c

Now since q=ne

Where n=number of electron

e=charge of electron

So, 0.16=(1.6×10^-19)n (here (^)=power)

So, n=0.16/(1.6×10^-19)

n=1×10^20

So number of electron =1×10^20