Question

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 seconds would be roughly [NCERT Exemplar Problems]
(a) 1020
(b) 1016
(c) 1018
(d) 1023

Answer 1

Answer:

I = Q/t

Q = It

Also It = number of electrons × charge of electron

It = NE

Where N is the number of electrons

1 × 16/ 1.6 × 10^-19 it comes to 10^ 20