Physics, asked by bhavish28, 2 months ago

A current of 1 ampere is passed through two resistance 1 ohm and 2 ohm connected in parallel. The current flowing in 2 ohm resistor will be​

Answers

Answered by sayanjalui9c96612
0

Answer:

1/3 A

Explanation:

Formula : -

I

1

=I

0

R

1

+R

2

R

2

I

2

=I

0

R

1

+R

2

R

1

I=1×[

1+2

1

]

I=

3

1

A

Answered by rengaramanujamr
1

Answer:

I in R₂ = 1/3 A or O.33 A

Explanation:

I = 1 A

R₁ = 1 Ω

R₂ = 2 Ω

1/R equivalent = 1/R₁ + 1/R₂

1/R eq = 1 + 1/2 = 3/2

R eq = 2/3

now, V = IR

V = 1 X 2/3

V = 2/3

I in R₂

I = V/R

I = 2/3 ÷ 2

∴ I = 1/3 A OR 0.33 A

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