Question

A current of 10 A flows through a conductor for two minutes.
(i) Calculate the amount of charge passed through unit area of cross section of the conductor .
(ii) If the charge of an electron is 1.6 x 10-19 C , then calculate the total number of electrons flowing.

Answer 1

I = 10A

T= 2min= 120 sec

$I=\frac{Q}{T}$

$10= \frac{Q}{120}$

$Q= 1200 C$

Now,

$e= 1.6*10^{-19}$

By Quantization of charge

$Q= ne$

$1200= n*1.6*10^{-19}$

$n= \frac{1200}{1.6*10^{-19} }$

$n=\frac{750}{10^{-19} }$

$n= 750*10^{19}$

Answer 2

Answer:

Charge, Q = 1200 C

Number of electrons, $n=7.5\times 10^{21}\ electrons$

Explanation:

It is given that,

Current, I = 10 A

Time, t = 2 min = 120 s

(i) Let Q is the amount of charge passed through unit area of cross section of the conductor. It is given by :

$I=\dfrac{Q}{t}$

$Q=I\times t$

$Q=10\ A\times 120\ s$

Q = 1200 Coulomb

(ii) Charge of an electron, $e=1.6\times 10^{-19}\ C$

Let n is the total number of electrons. It is given by using quantization of electric charge as :

$Q=ne$

$n=\dfrac{Q}{e}$

$n=\dfrac{1200}{1.6\times 10^{-19}}$

$n=7.5\times 10^{21}\ electrons$

Hence, this is the required solution.

Learn more

Electric current

https://brainly.in/question/8668202