Question

a current of 10 a is maintained in a conductor of cross section 10 metre square if the number density of free electron B9 into 1 metre square if the number density of free electron B9 into calculate the drift velocity of free electrons​

Answer 1

Answer:

It is simple .

Explanation:

The relation between current and drift velocity

i.e. 1 = v d.e.n.a

where I = current

v d = current velocity

e = electron

n = no . of electrons per unit volume

a = area of cross section

now v d = 1/nea

$= \: \frac{10}{1 \times {10}^{ - 4} \times 9 \times {10}^{7} \times 28 }$

$= 1.94 \times {10}^{ - 3} ms$

= 1.94 × 10 ^-3 m/s

Answer 2

Answer:

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