Question

A current of 10 a is maintained in a conductor of cross section 1 cm^2 .if number density of free electrons be 9ó10*28 m*-3 the drift velocity of free electons is

Answer 1

i = neAVd
Vd = i/neA
Vd = 10/ 9*10^14*1.6*10^-19*10^-4
Vd = 10/14.4*10^-9
Vd = 0.69*10^9
Vd = 7*10^8 m/s

Answer 2

Answer:

The drift velocity of free electron is $6.94\times10^{-8}\ m/s$

Explanation:

Given that,

Current I = 10 A

Area of cross section $A = 1\times10^{-2}\ m$

Number density of free electron $\rho=9\times10^{28}\ m^{-3}$

We know that,

The drift velocity of free electron is

$i=neAv_{d}$

$v_{d}=\dfrac{i}{neA}$

$v_{d} = \dfrac{10}{9\times10^{28}\times1.6\times10^{-19}\times1\times10^{-2}}$

$v_{d}=6.94\times10^{-8}\ m/s$

Hence, The drift velocity of free electron is $6.94\times10^{-8}\ m/s$.