A current of 1A is drawn by a filament of an electric bulb . Number of electrons passing through a cross section of the filament in 16 sec would be roughly ?
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HEY!!
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We have the relations:-
q=It and q=ne
So It=ne or n=It/e
Number of electrons n = 1×16/1.6×10^-19 = 10^20
____________________________
We have the relations:-
q=It and q=ne
So It=ne or n=It/e
Number of electrons n = 1×16/1.6×10^-19 = 10^20
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