Physics, asked by hemimukeshpatel296, 9 months ago

A current of 20 uA flows in a wire for 30 seconds.
Find the amount of charge and the number of free
electrons transferred through the wire.

Answers

Answered by harikairuvuru
3

Answer:

q=6*10^-4

n=3.75x10^-15

Explanation:

Given :

Current , I = 20 mA .

Time , t = 30 s .

amount of charge(q)=ixt

                              =20x10^-6 x30

                               =6x10^-4 columbs

number of free electrons=(6x10^-4)/1.6*10^-19

                                        =3.75x10^15

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