A current of 20 uA flows in a wire for 30 seconds.
Find the amount of charge and the number of free
electrons transferred through the wire.
Answers
Answered by
3
Answer:
q=6*10^-4
n=3.75x10^-15
Explanation:
Given :
Current , I = 20 mA .
Time , t = 30 s .
amount of charge(q)=ixt
=20x10^-6 x30
=6x10^-4 columbs
number of free electrons=(6x10^-4)/1.6*10^-19
=3.75x10^15
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