A current of 2A flows in a wire offering a resistance of 10 ohm . Calculate the energy dissipated by the wire in 0.5 hours
Answers
Answered by
2
Energy = W = Pt = I²Rt = 2²×10×0.5×3600
= 4×10×1800 = 72000 J
= 72kj Answer
Answered by
1
Answer:
72000
Explanation:
Energy will dissipate in the form of heat
Time=0.5 hours=1800 seconds
H=I^2RT
H=(2)^2*10*1800
H=72000
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